bash + print line every 10 min in bash

Question

I want to print by echo the following "still in process wait another 10 min" every 10 min

Please advice what condition needs to add before the echo command in order to print this line every 10 min?

Remark - counter increase by one every cycle (1 second) , I not want to add Additional delay ( sleep command ) to this script !!!!!

 Until   [    ]
 do
 Counter=1

 sleep 1

  let counter=$counter+1

  [ .... ] &&  echo " still in process wait another 10 min …."

 done 

Answer 1

Add another counter, and if that reaches 600, call echo and reset the counter. Repeat as needed.

So something like this should do:

let echocounter=$echocounter+1
if [ $echocounter == 600 ]; then echo "still in process wait 10 min ..."; $echocounter=0; fi

Answer 2

Use the modulo operator (bash specific syntax):

if [ $(($counter % 600)) -eq 0 ] ; then
  echo " still in process wait another 10 min .."
fi

Or more portable:

if [ `expr $counter % 600` -eq 0 ] ; then
  echo " still in process wait another 10 min .."
fi

Answer 3

What you want, is something like this:

#10 minutes from now
Increment_Timestamp=$(( $(date +%s) + 600 ))

while [  ...  ]
do
...
...
    # When now is 10 minutes ago, show the message.
    if [ $(date +%s) -lt "${Increment_Timestamp}" ]
    then
        ${Increment_Timestamp}=$(( $(date +%s) + 600 ))
        echo "Message"
    fi
done

Answer 4

I added some logic to check the time:

BOOL=true
MINUTES=$(date +"%M")
MINUTES=$(echo $MINUTES | sed 's/^0*//')

if $BOOL ; then
        BOOL=false

        if [ $MINUTES -le "49" ];then
                MINUTES10=$(($MINUTES+10))
        else
                MINUTES10=$(($MINUTES+50))
        fi
fi

if [ $MINUTES10 -eq $MINUTES ];then
        echo "message"
        BOOL=true
fi

Answer 5

You probably want the sleepenh program, which allows for "accurate sleeping". There's also a blog post about how it was used to solve a problem which required no oversleeping