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I have i file that contains 100000 line how i can get the lines from line# 5555 to line# 7777 under linux.

Thanks for all.

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1  
@ibrahim, consider accepting Kyle's answer (by ticking the green checkmark on the left) if it helped you –  Jonik Jan 12 '10 at 14:17

3 Answers 3

sed '5555,7777!d' <filename>

This will print lines 5555-7777 of the file inclusively.

Dennis Posted the following which I agree should be faster:

sed '5555,7777p; 7778q' filename

The following evidence that it should be faster:

$ n=1
$ while [[ n -le 100000 ]]; do echo $n >> sedtest2; n=$((n + 1)); done
$ strace -e trace=read -o sed1 sed '5555,7777!d' sedtest2
$ strace -e trace=read -o sed2 sed '5555,7777p; 7778q' sedtest2
$ wc -l sed1
149 sed1
$ wc -l sed2
14 sed1

In Bash only (for fun):

n=1
while read line; do 
    if [[ ($n -ge 5555) && ($n -le 7777)  ]]; then 
        echo $line
    elif [[ $n -gt 7777 ]]; then
        break
    fi 
    n=$(( $n + 1 ))
done < file
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Thanks ,This work for me –  ibrahim Jan 12 '10 at 13:53
    
I think your $n -gt 3 should be 7777 perhaps? Also, you can do if (( n >= 5555 )) for more "natural" looking numeric comparison operators (and the ability to leave off the dollar sign). And you can do ((n++)). –  Dennis Williamson Jan 12 '10 at 15:18

Quitting when you're done can speed things up:

sed '5555,7777p; 7778q' filename
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+1 , should be faster, updated my post to show why. –  Kyle Brandt Jan 12 '10 at 14:19

Either of these should work;

  • sed -n 'startnumber,*endnumber*p'
  • awk 'NR>=startnumber&&NR<=endnumber' file

Great question by the way ;)

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