How to grab a word from a file using sed or grep

Question

I am trying to pull a piece of text from a file to use as input for the next command. The word always starts with "JID_" and then some random numbers/characters after that.

For example :

        SelectorSet
            Selector: InstanceID = JID_001264193601, __cimnamespace = root/dcim

I want to assign a variable $JID to that string of characters. How do I pull it from the line ? sed or grep preferrably, but any method is fine.

Answer 1

This worked for me

(03:45 PM):(Jacob@houston)~$ egrep -o "JID_[0-9]+" bah | cut -d _ -f2

001264193601

Answer 2

Ok, I just hacked at it for a few minutes and came up with this :

grep JID job.txt | sed -e "s/.*InstanceID = //" -e "s/,.*//"

With output of this :

JID_001264194552

I think that will work.

Answer 3

This command:

var=$(sed -n 's/.*InstanceID = JID_\([0-9]\+\),.*/\1/p')
echo $var

will output this:

001264193601

for the given input.

If you want to keep the "JID_":

var=$(sed -n 's/.*InstanceID = \(JID_[0-9]\+\),.*/\1/p')