Grep a word from a file

Question

How can i grep a nearer word from a file ?

E.g

04-02-2010  Workingday
05-02-2010  Workingday
06-02-2010  Workingday
07-02-2010  Holiday
08-02-2010  Workingday
09-02-2010  Workingday

I stored above data in a file 'feb2010',

By this commend i stored date in one variable date=date '+%d-%m-%Y'

if date is 06-02-2010 , i want to grep "06-02-2010" with Workingday

and want to store the string "Workingday" in a variable

• How can i do this ?

• Is there any other option ?

Answer 1

Do you mean something like that?

DATE=$(date '+%d-%m-%Y')
DAY=$(grep $DATE feb2010 | awk '{ print $2 }')
echo $DAY

This greps for your $DATE and selects the second column for the output via awk and stores this output in the variable $DAY.

Answer 2

month = " 06-02-2010 Workingday " && grep search-string $month

Answer 3

Try

#!/bin/sh
variable=`grep "06-02-2010" feb2010`
OR
variable=grep "$(date +%d-+%m-%Y)" feb2010
echo $variable should return the good output

Answer 4

This question doesn't post an OS so here's how you would do this under windows powershell:

((select-string -path .\grepme.txt -pattern (get-date -uformat "%m-%d-%Y")).line).split(' ')[2]

Select-string is grep's equivalent