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Given this example:

mkdir a
ln -s a b
ln -s b c
ln -s c d

If I execute:

ls -l d

It will show:

d -> c

Is there a way for ls or any other linux command to show d -> c -> b -> a instead?

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I cross posted this as stackoverflow.com/questions/2320277/… I hope you don't mind. –  Paul Feb 23 '10 at 17:30
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3 Answers

up vote 6 down vote accepted

man readlink

It can do the following part with the -e option

$ mkdir testlink
$ cd testlink
pjb@pjb-desktop:~/testlink$ ln -s c b
pjb@pjb-desktop:~/testlink$ ln -s b a
pjb@pjb-desktop:~/testlink$ ls -l 
total 0
lrwxrwxrwx 1 pjb pjb 1 2010-02-23 08:48 a -> b
lrwxrwxrwx 1 pjb pjb 1 2010-02-23 08:48 b -> c
pjb@pjb-desktop:~/testlink$ echo foo > c
pjb@pjb-desktop:~/testlink$ cat a
foo
pjb@pjb-desktop:~/testlink$ readlink -e a
/home/pjb/testlink/c

note: readlink a by itself returns b

note #2: together with find -l, a utility to list the chains could easily be written in perl, but also has to be smart enough to detect loops

readlink will not output anything if you have a loop. This is better than getting stuck, I suppose.

pjb@pjb-desktop:~/testlink$ ln -sf a c
pjb@pjb-desktop:~/testlink$ ls -l 
total 0
lrwxrwxrwx 1 pjb pjb 1 2010-02-23 08:48 a -> b
lrwxrwxrwx 1 pjb pjb 1 2010-02-23 08:48 b -> c
lrwxrwxrwx 1 pjb pjb 1 2010-02-23 09:03 c -> a
pjb@pjb-desktop:~/testlink$ readlink -e a
pjb@pjb-desktop:~/testlink$ # (note: no output)
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just use namei:

$ namei d
f: d
 l d -> c
   l c -> b
     l b -> a
       d a
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TIL. This is a cool command. upvotes –  Tom O'Connor Nov 22 '11 at 14:52
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Here is a recursive function in Bash:

chain() { export chain; local link target; if [[ -z $chain ]]; then chain="$1"; fi; link=$(stat --printf=%N $1); while [[ $link =~ \-\> ]]; do target="${link##*\`}"; target="${target%\'}"; chain+=" -> $target"; chain "$target"; return; done; echo "$chain"; unset chain; }

On multiple lines:

chain() {
    export chain
    local link target
    if [[ -z $chain ]]
    then
        chain="$1"
    fi
    link=$(stat --printf=%N "$1")
    while [[ $link =~ \-\> ]]
    do
        target="${link##*\`}"
        target="${target%\'}"
        chain+=" -> $target"
        if [[ ! $target =~ / && $1 =~ / ]]
        then
            target="${1%/*}/$target"
        fi
        chain "$target"
        return
    done
    echo "$chain"
    unset chain
}

Examples:

$ chain d
d -> c -> b -> a
$ chain c
c -> b -> a
$ chain a
a

It requires stat(1) which may not be present on some systems.

It will fail if names contain backticks, single quotes, or "->". It gets stuck in a loop with symlink loops (this could be solved using an associative array in Bash 4). It exports a variable called "chain" without regard to whether it's already in use.

There may be other problems with it.

Edit:

Fixed a problem with some relative symlinks. Some still don't work, but the version below doesn't require the target of the link to exist.

Added a version that uses readlink:

chain ()
{
    export chain;
    local target;
    if [[ -z $chain ]]; then
        chain="$1";
    fi;
    target=$(readlink "$1");
    while [[ $target ]]; do
        chain+=" -> $target";
        if [[ ! $target =~ / && $1 =~ / ]]
        then
            target="${1%/*}/$target"
        fi
        chain "$target";
        return;
    done;
    echo "$chain";
    unset chain
}
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I've tested your script and it really works but I prefer something simpler so I've accepted the other answer even if incomplete. –  Kalecser Feb 23 '10 at 21:02
    
Nice script. Sometimes I want to see the entire chain, and readlink doesn't seem to show that. Java on Ubuntu is: /usr/bin/java -> /etc/alternatives/java -> /usr/lib/jvm/java-6-openjdk/jre/bin/java –  Stefan Lasiewski Oct 20 '10 at 19:33
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