Take the 2-minute tour ×
Server Fault is a question and answer site for professional system and network administrators. It's 100% free, no registration required.

Say I have 2 identical unmanaged gigabit switches on a network, A and B. There are computers connected to switch A, there are other computers connected to switch B. A and B are connected via 1 cable. So, the total (theoretical) bandwidth available for computers on A to talk to computers on B is 1Gbit/sec. All is well.

If I now connect a second cable between the switches, and make no other changes, would the total (theoretical) bandwidth between the 2 groups of computers go up to 2Gbit/sec?

share|improve this question
add comment

migrated from superuser.com Jul 11 '10 at 21:31

This question came from our site for computer enthusiasts and power users.

3 Answers

up vote 8 down vote accepted

No.

  • If your unmanaged switches are so simple that they don't do Spanning Tree Protocol (STP), connecting the second cable between them would cause a bridging loop, instantly saturating your network, making your network unusable until you remove the second cable.

  • If they do do STP, then only one of the switch-to-switch links will be used.

  • If you had manageable switches instead, then you could configure them to aggregate/trunk multiple ports together, getting a speed increase slightly less than the sum of the aggregated ports' speeds (there is some overhead from aggregation).

share|improve this answer
add comment

Not unless you configure link aggregation between the switches. Depending on your switch, if it even supports it, this may be referred to as NIC Teaming, Etherchannel, Port Channel, or trunking.

Note that if you simply plug in two connections without configuration such as this, you could seriously degrade your network by causing a loop, as @Spiff mentions in his post.

share|improve this answer
add comment

Could be. I could see the switches connecting A1 to B1 through one path, and A2 to B2 through another (A1 and A2 are next to A, B1 and B2 to B). The plain spanning tree protocol will always pick the same link, however.

share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.