bash script in unix - return full path and filename

Question

I want to design bash script in unix and this bash return full path because I want to use this file in other places.

Answer 1

Are you looking for the full path and filename of the running script?

#!/bin/bash

_my_name=basename $0

if [ "echo $0 | cut -c1" = "/" ]; then

 _my_path=`dirname $0`

else

 _my_path=`pwd`/`echo $0 | sed -e s/$_my_name//`

fi

echo " Filename: $_my_name"

echo "Absolute path: $_my_path"

echo "Full Path + Name: $0"

Answer 2

Give this a try if you have readlink on your system:

readlink -e filename

Answer 3

Since this question is not trying to answer the harder question of converting a path with symbolic links into a physical path (w/o any links), but rather just get the directory and/or full path to the original script, there is a simpler solution (broken down in this example into components for legibility, plus you may want to use any of these pieces individually):

#!/bin/bash
PROG_PATH=${BASH_SOURCE[0]}      # this script's name
PROG_NAME=${PROG_PATH##*/}       # basename of script (strip path)
PROG_DIR=$(cd "$(dirname "${PROG_PATH:-$PWD}")" 2>/dev/null 1>&2 && pwd)

echo "script directory is: $PROG_DIR"

Your test cases should involve calling this script with an absolute path, relative path, "sourcing" it, etc., and always ending up with the directory containing the script.