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If I want to display the IP address that is assigned to eth1, how can I do this in Bash?

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3 Answers 3

up vote 7 down vote accepted

Try this (Linux)

/sbin/ifconfig eth1 | grep 'inet addr:' | cut -d: -f2| cut -d' ' -f1

or this (Linux)

/sbin/ifconfig eth0 | awk -F ' *|:' '/inet addr/{print $4}'

or this (*BSD)

ifconfig bge0 | grep 'inet' | cut -d' ' -f2

or this (Solaris 10)

ifconfig e1000g0 | awk '/inet / {print $6}'

Obviously change the interface name to match the one you want to get the information from.

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2  
worked also ifconfig eth1| awk -F ' *|:' '/inet addr/{print $4}' –  user47556 Oct 27 '10 at 11:37
1  
On *BSD systems the ifconfig output is a bit different - ifconfig bge0 | grep 'inet' | cut -d' ' -f2 will work (substitute your appropriate interface name in place of bge0, obviously) –  voretaq7 Aug 15 '11 at 18:08
    
ip addr show eth1| grep inet|awk '{print $2;}' –  navaho Aug 16 '11 at 22:18

maybe this will help

ifconfig eth1
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i know this , and its show all info i need just to get ip –  user47556 Oct 27 '10 at 11:00
    
like inet addr:74.86.xx.xx only the nemric ip here show in echo result , –  user47556 Oct 27 '10 at 11:01

A better way: get ip adress from command "ip", because "ifconfig" is out of date. Otherwise you will get a problem on using "ifconfig", because the output of ifconfig is language dependend.

I use this command to get all IPs (IPv4):

ip addr show | grep -o "inet [0-9]*\.[0-9]*\.[0-9]*\.[0-9]*" | grep -o "[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*"
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ifconfig has the advantage of existing on systems that aren't Linux... –  voretaq7 Dec 7 '12 at 3:59

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