If I want to display the IP address that is assigned to eth1, how can I do this in Bash?
14 Answers
Try this (Linux)
/sbin/ifconfig eth1 | grep 'inet addr:' | cut -d: -f2| cut -d' ' -f1
or this (Linux)
/sbin/ifconfig eth0 | awk -F ' *|:' '/inet addr/{print $4}'
or this (*BSD)
ifconfig bge0 | grep 'inet' | cut -d' ' -f2
or this (Solaris 10)
ifconfig e1000g0 | awk '/inet / {print $6}'
Obviously change the interface name to match the one you want to get the information from.
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1On *BSD systems the ifconfig output is a bit different -
ifconfig bge0 | grep 'inet' | cut -d' ' -f2
will work (substitute your appropriate interface name in place ofbge0
, obviously)– voretaq7Aug 15, 2011 at 18:08 -
1
As @Manuel mentioned, ifconfig
is out of date, and ip
is the recommended approach going forward.
ip -f inet addr show eth1
and to use @bleater's sed or @Jason H.'s awk to filter the output (depending on if you want the mask)
ip -f inet addr show eth1 | sed -En -e 's/.*inet ([0-9.]+).*/\1/p'
ip -f inet addr show eth1 | awk '/inet / {print $2}'
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ip -f inet6 addr show eth1 | sed -En -e 's/.*inet6 ([0-9a-fA-F:]+).*/\1/p'
for ipv6 Jun 30, 2022 at 14:39 -
ip -f inet addr show lo | awk '/inet / {print $2}'
gives me127.0.0.1/8
, not the desired127.0.0.1
.– AbdullOct 31, 2022 at 10:40 -
ip -4 -o addr show eth0 | awk '{print $4}' | cut -d "/" -f 1
if you don't like sed Feb 13, 2023 at 12:02
On a Linux system:
hostname --all-ip-addresses
will give you only the IP address.
On a Solaris system use:
ifconfig e1000g0 | awk '/inet / {print $2}'
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2From the hostname(1) man page:
Avoid using this option; use hostname --all-ip-addresses instead.
– bleaterNov 14, 2017 at 1:06 -
To obtain both IPv4 and IPv6 IP addresses with netmasks just try:
ip a l eth1 | awk '/inet/ {print $2}'
Or without netmasks (can't imagine why you need an IP address without a mask):
ip a l eth1 | awk '/inet/ {print $2}' | cut -d/ -f1
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5"can't imagine why you need an IP address without a mask" Simple, there's very few clients that support it. You can't ping 1.1.1.1/32. 1.1.1.1/32 would return a 404. You can't point an A record to it, nor insert it into a reverse proxy config, nor tunnel to it, nor put it into /etc/hosts.– copycatMar 3, 2021 at 1:46
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"l" stands for list (not documented in inline help (iproute2 version 5.5.0), only documented in manpage).– 3r1dJul 27, 2023 at 3:33
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@red0ct for anyone writing a script where the IP needs to be an input for example. Pairing an IP to a Mac address, the cidr range is already known by the system that wants this information. Passing the cidr range would require more processing somewhere down the line, so it's just a matter of where you want to do that work. Feb 28 at 20:10
A better way: get ip adress from command "ip", because "ifconfig" is out of date. Otherwise you will get a problem on using "ifconfig", because the output of ifconfig is language dependend.
I use this command to get all IPs (IPv4):
ip addr show | grep -o "inet [0-9]*\.[0-9]*\.[0-9]*\.[0-9]*" | grep -o "[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*"
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1
ifconfig
has the advantage of existing on systems that aren't Linux...– voretaq7Dec 7, 2012 at 3:59 -
1
Works well on various linux:
ip -brief address show eth0 | awk '{print $3}' | awk -F/ '{print $1}'
On recent OS and tools versions, using JSON interface should work too, e.g.:
ip -json addr show docker0 \
| jq '.[].addr_info[] | select(.family == "inet").local'
Which yields on my machine:
"172.17.0.1"
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To make it run from a subprocess:
local_ips = subprocess.check_output(["ip -json addr show eth0 | jq -r '.[].addr_info[] | select(.family == \"inet\" | @sh).local'"], shell=True, encoding='utf8')
Feb 28 at 20:07
ip addr show dev eth0
if you want to see all addresses for one interface
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Welcome to the server fault community. How does this answer differ from previously given answers? Jan 22 at 9:58
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Thanks for the welcome @JohnK.N. The previously given answers have a lot of grep, sed and awk that felt unnecessary for answering the simple question asked. The accepted answer uses a deprecated command. If you feel my answer isn't valid or helpful I can certainly remove it.– bryvo01Jan 23 at 13:06
One liner with sed:
ifconfig wlan0 | sed -En -e 's/.*inet ([0-9.]+).*/\1/p'
Replace wlan0 with the desired interface.
I tried the accepted answer on CentOS 7, but it does not work.
/sbin/ifconfig eth0 | grep 'inet ' | tr -s ' ' | cut -d" " -f3
worked for me, in case someone else is also running into the same problem.
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1As mentioned by @Manuel and @pstanton,
ifconfig
should be avoided. It's actually removed in some newer distros. This is probably why your answer was downvoted. May 10, 2018 at 19:30
This is what I use:
ip r s | awk '/eth0/ {print $7}'
will print, for example: 192.168.0.1
On MacOS I use ipconfig getifaddr <interface-name>
The command is listed under the BSD System Manager's Manual
.