Find directories not containing a certain subdirectory

Question

I know I can do this to get a list of directories inside /vz/root:

find /vz/root/ -type d -maxdepth 1 -exec echo {} \;

But how can I edit this to only list the directories that do not contain a subdirectory called "php-5.3.3"? So if there's 3 directories /vz/root/101, /vz/root/102, and /vz/root/103, and two of them contain php-5.3.3 subdirectory, it would only echo the path of the one that doesn't have it.

Answer 1

Try

find /vz/root/ -maxdepth 1 -type d  \! -exec test -d '{}/php-5.3.3' \; -print | grep -v php-5.3.3 | uniq -w 12 | grep -v '^/vz/root/$'

Answer 2

If you want to exclude the paths that contain php-5.3.3, you can simply use grep -v

find /root/ -maxdepth 1 -type d -exec echo {} \; | grep -v php-5.3.3

Answer 3

You can use ! as not operator.

find /vz/root/ -type d -maxdepth 1 ! -ipath '*php-5.3.3*' -exec echo {} \;

That would list all the directories under /vz/root/ except the ones that has php-5.3.3 in their path name.

Answer 4

It is possible to take something that almost solves it with find and use find2perl to create a Perl program that does the same thing. Then modify the Perl script to do something advanced. I won't enumerate though because you asked for a variation on the find command and this is outside the scope of your request. Plus, you'd have to know some Perl and I don't want to start a flamewar.