I want to write something detecting where PHP is installed and then execute php after that eg:
So I can get it to detect the php I want to use and stick it in a variable, but I don't know how to get it to execute the following php file after. Here's a skeleton of what I've got:
#!/bin/bash if [ -e /usr/local/zend/bin/php ]; then PHP=/usr/local/zend/bin/php else PHP=/usr/bin/php fi $PHP <execute php>
Edit - thanks got it, just needed exec $PHP "$@"