Server Fault is a question and answer site for system and network administrators. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I have a Debian server with a IPv6 Tunnel (from sixxs) and an IPv4 Ubuntu Client. Now i want to make a tunnel from the client to the server, so that i can surf with IPv6 from the client.

Is there a simple solution or should i request another tunnel (ar a subnet) for my client?

Thanks in advance.

share|improve this question

migrated from Feb 14 '11 at 2:32

This question came from our site for professional and enthusiast programmers.

up vote 3 down vote accepted

SixXS only provide a single IPv6 address with a tunnel. Because in IPv6 it is not possible to NAT, you will require a subnet in order to route your other machine through the tunnel.

Is the other machine on the same LAN? If so, the best thing to do is to request a subnet from SixXS and route a /64 from the /48 subnet you are allocated onto your LAN.

If the machine is on a separate Internet connection, it would probably be more economical to request another tunnel, although requesting a SixXS subnet and routing it yourself via something like OpenVPN is not infeasible either.

share|improve this answer
The machine is in the same LAN. So i go to request a subnet. Thanks for your answer. :-) – fwaechter Feb 15 '11 at 16:32

You might consider getting a tunnel with Hurricane Electric, which will provide you with a routed /64. Then you could (in theory) set up a VPN.

The easiest option would, indeed, probably be to get a second tunnel from SixXS. An anything-in-anything tunnel would be a good option for your Ubuntu client. Or terminate another routed tunnel locally at your router, or use 6to4, or... the options are endless. ;-)

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.