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When I try to exit from my Linux server I get the message:

There are stopped jobs.

: Is there a single command to kill these?

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Additional examples in thie U&L Q&A: unix.stackexchange.com/questions/124428/… –  slm Apr 12 at 20:25
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5 Answers

up vote 24 down vote accepted

To quickly kill all the jobs running under the bash, enter:

kill `jobs -p`

jobs -p list process ID of the job's. kill jobs -p send TERM signal to all job's.

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8  
-1 for "kill Jobs" –  Tibor Aug 10 '12 at 21:44
    
didn't work when the job was "sudo su". i.e. sudo kill `jobs -p` didnt work but explicitly typing PID did. –  user13107 Oct 27 '12 at 18:12
    
Why is this upvoted so highly? It's wrong. If the processes are stopped, then a kill such as this will do nothing, since the processes are stopped, they won't process the SIGTERM (-15) that is sent to them by default. –  slm Apr 12 at 20:18
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Try typing this:

kill -9 $(jobs -p)
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6  
That should do it, but I think he should send first a SIGTERM (-15) before sending a SIGKILL (-9). So perhaps proposing something like "kill $(jobs -p) ; sleep 3s ; kill -9 $(jobs -p)" would be better. Sending SIGTERM first the jobs may be able to do a clean exit (freeing allocated resources, etc). –  rems Feb 25 '11 at 10:49
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Kevin Duke, your answer is the one that worked for me. I couldn't vote because I don't have 15 in reputation. kill -9 $(jobs -p) –  user131776 Aug 10 '12 at 21:33
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The accepted answer would kill all jobs (which is sufficient in this case) and not merely the stopped ones. Should you want to kill only the Stopped ones, run:

kill $(jobs -l | grep Stopped | cut -d' ' -f3)
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The easiest way is actually to simply immediately retry the exit; bash will take that to mean "kill all stopped jobs and exit".

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for x in `jobs -p` ; do kill -9 $x ; done
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2  
you can add code formatting for this line to make it easier to read. –  drcelus Feb 26 '13 at 10:54
    
Can you take a look at your formatting again - use four spaces at the start of the line to mark a block as code (rather than using backtick). Right now it isn't clear whether you are using backticks in your code, or trying to display code using backticks. –  dunxd Feb 26 '13 at 11:39
    
The formatting is fine. we have to pass the jobs -p using backticks else it wont consider as a command, and it will throw an error. –  monu Feb 27 '13 at 6:01
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