How to run mysql commands through shell script?

Question

mysql -u root -pmysql;

SELECT TABLE_NAME AS "Table Name", table_rows AS "Quant of Rows", ROUND((data_length + index_length)/1024/1024,2) AS "Total Size Mb"  FROM information_schema.TABLES WHERE information_schema.TABLES.table_schema='database_name';

I want to create a shell script which will execute these command and return the result.

How may i run this commands through shell script ?

Answer 1

Yet another answer...

mysql -uroot -pmysql -B --skip-column-names -e'SELECT TABLE_NAME AS "Table Name", table_rows AS "Quant of Rows", ROUND((data_length + index_length)/1024/1024,2) AS "Total Size Mb"  FROM information_schema.TABLES WHERE information_schema.TABLES.table_schema="database_name"'

Also, if you are going to have the password in the script, you should secure it so it isn't readable by people you don't wanting to know the password.

Answer 2

mysql -u root -pmysql << eof
SELECT TABLE_NAME AS "Table Name", table_rows AS "Quant of Rows", ROUND((data_length + index_length)/1024/1024,2) AS "Total Size Mb"  FROM information_schema.TABLES WHERE information_schema.TABLES.table_schema='database_name';
eof

Answer 3

Or, equivalently, something like this:

echo 'SELECT TABLE_NAME AS "Table Name", table_rows AS "Quant of Rows", ROUND((data_length + index_length)/1024/1024,2) AS "Total Size Mb" FROM information_schema.TABLES WHERE information_schema.TABLES.table_schema="database_name";' | mysql -u root -pmysql

EDIT: fixed quoting.