Working with arrays in puppet

Question

I have a variable $IP = [ "91" , "92" ]and $IPPriveeInstance = "10.248.33.$IP".

You guessed it, I want to use this variable 2 times,but when I print IPPriveeInstance, I got the output as 10.248.33.9192.

This should be asked on stackoverflow.com. I have put in a request for it to be transferred there.
@Caleb: Puppet is a programming language, but it's a very specific very limited programming language for system administration. It's totally on topic here, even if it is also on-topic on StackOverflow.
What are you expecting to print? If you set the IPPriveeInstance variable to one address or the other, you'll only have... one address. Give us more information on what you're trying to accomplish (populating a config file? passing those in to a module?), and we'll be able to help.
Hi im trying to test if files (named with IPPriveeInstance exist in client) so the need of an array as you see.Thanks

Nan Liu · Answer 1 · 2011-04-15 21:03:13Z

Puppet does not iterate array items. The example below demonstrates with inline_template, but you should use a custom function to perform this task.

$ip      = ['91', '92']
$address = '10.248.33.'
$array   = inline_template("<%= ip.collect{|x| address+x.to_s} %>")

Kyle · Answer 2 · 2011-04-12 15:44:19Z

You're trying to reference the full array at once when you want the individual parts of the arrays separately. Try this:

$IPPriveeInstance = "10.248.33.$IP[0]"
$IPPriveeInstance = "10.248.33.$IP[1]"

The first index in an array is always zero.

2 Answers