Take the 2-minute tour ×
Server Fault is a question and answer site for professional system and network administrators. It's 100% free, no registration required.

We decide to use Active Directory Lightweight Directory Services (AD LDS) for our application. But we cannot find the guide for clustering this service. Can anybody suggest or give a link to the best-practice for clustering Active Directory Lightweight Directory Services (AD LDS).

share|improve this question
    
This is a duplicate question. serverfault.com/questions/281672/… –  Mark Arnott Jun 22 '11 at 16:07
1  
No. AD LDS is not the same as AD –  Sasha Jun 23 '11 at 7:06

1 Answer 1

up vote 0 down vote accepted

Just as with AD, you don't cluster AD LDS using MSCS. You configure it to have replication across LDS servers (just as AD, so you don't have shared storage like you need with clusters). There's (as near as I can tell) a feature called a Service Connection Point, which publishes the instance information into AD, so that clients can just bind to an instance, not one or more specific LDAP servers (LDS servers).

/edit - also, it appears that you can use NLB to front-end AD LDS. That will also handle the front-end connection in a HA manner.

share|improve this answer
    
Thanks. But what about logical "cluster" IP. Can I access service (built in such way) using one IP for two physical instances of the LDS servers? –  Sasha Jun 20 '11 at 20:00
    
The MS docs that I skimmed through seem to indicate that defining a Service Connection Point is what does that. In normal AD, the dcpromo process adds every DC's IP to the A records for the domain. I imagine that publishing the SCP is a similar process. But really, at this point, you would do yourself the best favor by actually reading the vendor documentation and then coming back here with any further questions. –  mfinni Jun 20 '11 at 20:28
    
Thanks. I'll do my best. –  Sasha Jun 20 '11 at 21:04

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.