How Can I use grep so as to return me all matches for not only entire expression but also any part of the expression.
example:
grep "foobar" foo
where foo contains text foo should give me a match
5
-
Why not just grep for "foo" in the first place then?– Ignacio Vazquez-AbramsSep 5, 2011 at 12:42
-
I want to check if a password contains any dictionary words. Thats why– debtkSep 5, 2011 at 13:07
-
Your question still doesn't make sense, any part of 'foobar', includes f, fo, foo, foob, fooba, foobar, o, oo, oob, ooba, oobar, ob, oba, obar, b, ba, bar, a, ar. If you have a dictionary full of words and you're grepping with it, it's already working as required (fish will match fishing), if your dictionary doesn't contain all word variants (only has fishing and not fish) that's a different issue– EightBitTonySep 5, 2011 at 13:22
-
@Alek Sood: you store your passwords in plaintext????!!!!!– symcbeanSep 5, 2011 at 14:13
-
@symncbean haha...No dude! whats stored in plain text is a list of passwords not allowed– debtkOct 25, 2011 at 15:41
Add a comment
|
1 Answer
Why don't you simply grep on "foo". Without any flag, grep matches everything ; while the flag "-w or --word-regexp" does an exact matching.
