egrep matching group not printing?

Question

I'm trying to create a bash script that will grep lines from a file using egrep. I've created the regex that should group the information I want, the issue is trying to get the output. I've been testing it with the following command but nothing is printed when ran. How do I print the multiple lines between the -{80} and Disconnected?

egrep -E "^-{80}$\r?\n?([:ascii:]*)Disconnected from Server" testing.txt

File: testing.txt

Connected to the server: name here

Some header text.
More text to go though...
--------------------------------------------------------------------------------
The information that I want, would be in here;

Including this line as well #$
and this one.

Disconnected from Server...

Answer 1

You might be better off using a tool like awk.

awk '/^----+$/ {flag=1;next} /Disconnected from Server/{flag=0} flag {print}'

See: http://nixtip.wordpress.com/2010/10/12/print-lines-between-two-patterns-the-awk-way/

Answer 2

Just because I eventually worked it out here's a sed version

sed -n '/^-----\+$/,/^Disonnected/ {/^----\+$/d;/^Disonnected/d;p;}' testing.txt

This operates on all lines between /RE1/ and /RE2/, if the input matches /RE1/ or /RE2/ then it is deleted otherwise it is printed.