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We've setup a cron-based invocation of a Java program every minute. This Java program invocation is written in a shell script and is setup as cron job. Each invoked Java program is directed to its own separate log file (using date & time as file name with precision upto minutes) as shown below:

calljavaprogram.sh

DATE=`date +%Y-%m-%d_%H-%M`
/usr/java/jdk1.6.0/bin/java -Xms512m -Xmx1024m -XX:+HeapDumpOnOutOfMemoryError MyJavaProgram 2>&1 >> $DATE.log | tee -a $DATE.err >> $DATE.log &

For example, I can find out the currently running Java process (MyJavaProgram) at any time using the following command:

[root@user ~]# ps -ef |grep MyJavaProgram
user    4321     1  0 Oct17 ?        00:00:17 /usr/java/jdk1.6.0/bin/java -Xms512m -Xmx1024m -XX:+HeapDumpOnOutOfMemoryError MyJavaProgram
user    5747     1  0 Oct17 ?        00:00:11 /usr/java/jdk1.6.0/bin/java -Xms512m -Xmx1024m -XX:+HeapDumpOnOutOfMemoryError MyJavaProgram

My question is, I want to find out the actual log file name to which the currently executing Java process (MyJavaProgram) is writing to. So, for example, if there are 2 MyJavaProgram currently executing, I want to know the log file name of each process. In this case, I'm interested/want to know the .log extension file, though there are 2 extensions - .log and .err.

NOTE: Log file name is generated in this pattern, 2011-10-17_19-28.log, for example. Our server is RHEL4.

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1 Answer 1

up vote 2 down vote accepted

The command "lsof" might help you out here.

lsof | grep $PID |grep .log

or similar should yield you with a list of files that process is accessing.

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1  
Another way of doing the same thing is ls -l /proc/$PID/fd/*.log You can also make the above command more efficient by using lsof -p $PID | grep '\.log' –  Ladadadada Oct 18 '11 at 9:50
    
@Antitribu: If there are multiple MyJavaProgram Java process currently running, how do I pass PID dynamically to lsof command? –  Gnanam Oct 18 '11 at 10:01
    
@Gnanam , you mean something like for i in `ps aux |grep java |grep -v grep |awk '{print $2}'`; do echo $i; lsof |grep $i |grep \.log; done ? Flavor to taste –  Antitribu Oct 18 '11 at 10:10
    
@Antitribu: Actually, I didn't intend to mean/ask anything specifically, but I'm just trying to find out whether multiple $PID can be passed dynamically to lsof command. –  Gnanam Oct 18 '11 at 10:50
    
@Gnanam all good, lsof just gives you a list of open files that you can parse any way you wish. –  Antitribu Oct 18 '11 at 11:06

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