Server Fault is a question and answer site for system and network administrators. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I have Vista x64 installed on a 75 GB partition. I just noticed it was almost full and started snooping around for the space hog. It turns out it's my AppData\Roaming folder. It's consuming nearly half the partition. I don't know what this folder is, but by the name I'd guess it has something to do with roaming profiles. We don't use roaming profiles.

Can anyone tell me about this folder, why it is consuming so much disc space, and how I can get it back?

share|improve this question
up vote 3 down vote accepted

You need to drill further down to see what's using all the space. Applications you run store data in subfolders of that folder. Locating the particular subfolder that's eating up all the disk space will help pinpoint the application.

An aside: A neat little freeware utility that I like to use to show subfolder sizes, and one that I would use in this instance, is TreeSize Free, available from:

share|improve this answer
I saw two other folders in there named "Local" and "LocalLow" and assumed local application data would reside exclusively in them. That would make too much sense I guess. Anyway, I found the offending application. Thanks. – raven Jul 6 '09 at 20:52
+1 for treesize – Mark Henderson Jul 6 '09 at 21:37

Just for clarity, that folder does not specifically deal with Roaming Profiles. It is the "new" Vista location for your Application Data.

XP: Documents and Settings\$USER$\Application Data
Vista: Users\$USER$\AppData\Roaming

As Evan said, check the subfolders to see which Application is writing data there and consuming your space.

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.