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C:\Users\bacadmin>netstat -anov | find ":80 "
TCP 0.0.0.0:80 0.0.0.0:0 LISTENING 3976
TCP 0.0.0.0:80 0.0.0.0:0 LISTENING 3808
TCP [::]:80 [::]:0 LISTENING 3976

The one with the process id of 3976 is a Jetty that is configured to start with setReuseAddress(false). How is it possible?

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Do you have ipv6 enabled? :: seems to imply it is listening on the ipv6 interface, –  Oneiroi Mar 8 '12 at 12:25

1 Answer 1

Agreed with Oneiroi, the TCP [::]:80 [::]:0 is the IPv6 equivalent to the TCP 0.0.0.0:80 0.0.0.0:0 (which is IPv4)

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But how do you explain the first two lines? –  Vic Mar 26 '12 at 13:03
    
0.0.0.0:80 means "every IP that the computer provides on port 80". So it listens on the loopback (127.0.0.1) as well as your internal network address (for example 192.168.1.1) –  Cold T Mar 26 '12 at 13:18
    
Yes, but it seems like there are two processes listening on the same port, isn't it? –  Vic Mar 26 '12 at 17:06
    
yes that is possible to have two processes listening on the same port. If you are worried, you can kill these from Task Manager (you will need to go view and add the Process ID column in), then restart and should be fine. –  Cold T Mar 27 '12 at 10:43

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