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How can I get details of the page that taking more than 10000 sec.


I want to Out put as below as it is taking more than 10000 sec:

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up vote 1 down vote accepted

I know you said "grep", but here's an awk variation anyway. Try

awk -F 'pageTime=' '{ if ($2 > 10000) print $0 }' /path/to/your/logfile
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If your datas are from a file named file : egrep '=[0-9]{5}' file In this case you will have the 10000s too (as it have 5 digits)

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