I have bash code like this (Mac OS X):
foo.sh | tee foo.log
echo $?
The problem is that $? contains the exit code of tee and not the exit code of foo.sh. How do I get the exit code of foo.sh?
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stackoverflow.com/questions/6871859/…– DevdasAug 12, 2012 at 18:39
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2 Answers
The environment variable $PIPESTATUS is an array of exit statuses for all processes in a pipeline.
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2Probably for the same reason there's a button to "answer your own question".– SkaperenAug 12, 2012 at 20:03
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@Patrick I didn't know the answer when I asked the question, but did some more digging and found it. Aug 13, 2012 at 0:44
Also use a subshell:
tm@hoegaarden:~$ cat foo.sh
#!/bin/bash
echo "stuff and junk"
exit 123
tm@hoegaarden:~$ (./foo.sh ; echo $? > ./retval ) | tee output
stuff and junk
tm@hoegaarden:~$ cat retval
123
