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I have been given the following IP 192.168.14.137/25 and asked to divide the network into 2.

This is what I've come up with:

  • The subnet mask is 255.255.255.128
  • The network address is 192.168.14.128

There are a total of 128 available addresses (including the network address and broadcast address)

To divide the network we create two subnets:

  • 192.168.14.128/26
  • 192.168.14.192/26

This will have a subnet mask of 255.255.255.192

Am I missing anything, or is this correct?

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marked as duplicate by David Schwartz, MadHatter, RobM, Tom O'Connor, Massimo Sep 23 '12 at 18:16

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

5  
Please see the FAQ; this is a site for professional sysadmins and this looks like a homework question. That said, I'm assuming it's a typo, but you've dropped to 68 instead of 168. Otherwise, it's all fine. –  SmallClanger Sep 23 '12 at 6:25
    
Fair enough, thank you. (It is a hw question, but I couldn't tag it as hw, now i know why.) –  kylex Sep 23 '12 at 6:36
2  
you have seen this question? serverfault.com/questions/49765/how-does-ipv4-subnetting-work –  Zoredache Sep 23 '12 at 9:26

1 Answer 1

up vote 3 down vote accepted

Yes, everything is correct in your calculations.

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