Take the 2-minute tour ×
Server Fault is a question and answer site for professional system and network administrators. It's 100% free, no registration required.

I have this error that comes up every time I do an apache2 restart and am just wondering if anyone can shed some light on the issue. Is it something I even need to worry about at all?

I have had it for a while with no problems, but had a server crash recently and while this is obviously unrelated I will be willing to try anything to make sure it doesn't happen again. This includes cleaning up these types of errors to make it easier to troubleshoot in the future.

[Sun Nov 04 10:51:46 2012] [error] python_init: Python version mismatch, expected '2.6.5+', found '2.6.6'.
[Sun Nov 04 10:51:46 2012] [error] python_init: Python executable found '/usr/bin/python'.
[Sun Nov 04 10:51:46 2012] [error] python_init: Python path being used '/usr/lib/python2.6/:/usr/lib/python2.6/plat-linux2:/usr/lib/python2.6/lib-tk:/usr/lib/python2.6/lib-old:/usr/lib/python2.6/lib-dynload'.
[Sun Nov 04 10:51:46 2012] [notice] mod_python: Creating 8 session mutexes based on 256 max processes and 0 max threads.
[Sun Nov 04 10:51:46 2012] [notice] mod_python: using mutex_directory /tmp 
[Sun Nov 04 10:51:46 2012] [notice] Apache/2.2.16 (Debian) DAV/2 SVN/1.6.12 mod_ssl/2.2.16 OpenSSL/0.9.8o mod_fcgid/2.3.6 PHP/5.3.3-7+squeeze14 with Suhosin-Patch mod_python/3.3.1 Python/2.6.6 mod_ruby/1.2.6 Ruby/1.8.7(2010-08-16) mod_perl/2.0.4 Perl/v5.10.1 configured -- resuming normal operations

Any help will be appreciated, I am a bit of a n00b when it comes to this sort of stuff ;)

share|improve this question

1 Answer 1

up vote 2 down vote accepted

The message is from mod_python, telling you that it was compiled with Python 2.6.5 but the system's Python installation is 2.6.6. It will still work regardless of the version mismatch.

Anyway, mod_python hasn't seen any development in a number of years and has been deprecated by most projects in favour of alternatives like mod_wsgi.

share|improve this answer
    
Thanks Pedro ;) –  jezhug Nov 4 '12 at 0:42

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.