Take the 2-minute tour ×
Server Fault is a question and answer site for system and network administrators. It's 100% free, no registration required.

Few questions after the following commands:

mount -o bind /new_disk/home/user/ /home/user/

mount -o bind --no-mtab /new_disk/home/user/ /home/user/
  1. What is the difference between the two commands other than " Mount without writing in /etc/mtab. This is necessary for example when /etc is on a read-only filesystem."

  2. What is the difference between mount -o bind and mount --bind ...if there are

  3. Let's suppose i don't know there is a partition mounted using -o bind --no-mtab...where can I find if there is any mount point with bind ? The only way i can detect this is grep user /proc/mounts but in that line there is no info abut bind.

Thank you.

share|improve this question

1 Answer 1

  1. None.
  2. None.
  3. Hmm, never knew that. You could find duplicate source devices and stat both mountpoints. If inodes differ, you have a bind mount:

    dennis@lightning:/tmp/foo1$ grep uuid /proc/mounts
    /dev/disk/by-uuid/ae2c3836-ea2d-4d0e-8409-75d682889d1f / ext3 rw,relatime,errors=remount-ro,barrier=1,data=ordered 0 0
    /dev/disk/by-uuid/ae2c3836-ea2d-4d0e-8409-75d682889d1f /tmp/bar1 ext3 rw,relatime,errors=remount-ro,barrier=1,data=ordered 0 0
    
    dennis@lightning:/tmp/foo1$ stat -c %i /tmp/bar1 /
    1228938
    2
    

    However, if you bindmount one mountpoint to another (e.g. bindmounting / to /tmp/bar1), the inode numbers will be the same. Thus making it impossible to distinguish between a bind-mounted filesytem or a device simply mounted twice.

share|improve this answer
    
i hope there is a way of getting partitions mounted with bind if --no-mtab is given. I'll wait a few more days maybe someone will give me a hint :) but thank you for your explains –  Ionut Dec 17 '12 at 23:24

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.