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If a IP address is 192.168.112.28 what does each quadrant represent in this IP address?

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closed as not a real question by Shane Madden, EEAA, Michael Hampton, Jacob, mdpc Feb 27 '13 at 5:33

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question.

    
possible duplicate of How does IPv4 Subnetting Work? –  EEAA Feb 27 '13 at 4:38
    
An IPv4 address is 32 bits, the pieces are simply the bytes in the address written in decimal. –  vonbrand Feb 27 '13 at 13:29
    
for reference, its also called an octet. –  Sirex Feb 27 '13 at 23:33

2 Answers 2

It is a 32-bit unsigned integer, converted into four 8-bit unsigned integers so that humans can read it more easily. The numbers are represented most-significant-bit-first.

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Which is why you can ping 3232264220 and it will work (well, if you have a 192.168.112.28 on your network anyway) –  Mark Henderson Feb 27 '13 at 4:46
    
thanks for the reply, yes.. they are 32-bit unsigned integers. but i want to know what exactly those integers represent. ex: 192/11000000 -represents a port or something –  chamz33 Feb 27 '13 at 5:31
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I don't understand what you're trying to ask there. Ports are not part of an IP address, and that example doesn't correspond to anything. –  Michael Hampton Feb 27 '13 at 5:33
    
@frozenhaart Don't try to invent meaning where there is none. –  ceejayoz Feb 27 '13 at 23:44

IP address consists of 32 bits, it is represented as 4 octets of numbers from 0-255 instead of binary form. For example, the IP address: 192.168.112.28 in binary form is 11000000.10101000.01110000.0011100

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