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I have a Windows Server machine with DNS set up in the following way:

Zone: home.local
Domain: apache
    A  (same as parent)   192.168.2.4
    A   xml               192.168.2.4

I want to be able to connect to 'apache' and 'xml.apache', and be taken to the same address - however this isn't working. On both the server and another machine, I get the following:

> nslookup apache
Server: UnKnown
Address: 192.168.2.2

Server: apache.home.local
Address: 192.168.2.4


> nslookup xml.apache
Server: UnKnown
Address: 192.168.2.2

Server: apache.home.local
Address: 192.168.2.4

The only difference being the first result is localhost & loopback address on the dns server. Pings do this:

> ping apache
Reply from 192.168.2.4

> ping xml.apache
Could not find host.

> ping xml.apache.home.local
Reply from 192.168.2.4

I have tried /flushdns and net stop dnscache but neither worked. There is nothing untoward in my hosts file.

How can I get this working?

1 Answer 1

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AFAIK, you need to use the FQDN, which would be xml.apache.home.local.

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  • To add, you could change your search suffix (or add a 2nd one) as "apache.home.local" if you want to ping "xml" but pinging "xml.apache" won't work.
    – TheCleaner
    Sep 5, 2013 at 21:07

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