Server Fault is a question and answer site for system and network administrators. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I'm trying to set up a repo that contains both CentOS 6.4 and 5.9 packages. The machine itself is 6.4.

I've created a GPG key and have been able to sign my 6.4 packages no problem. When I create them for 5.9 though I get header errors. I realize that the versions of RPM are different, so I installed 4.2 (the version that ships with 5.9) and tried signing with that... it still doesn't work.

[root@usch1ksv01 RPMS]# /usr/local/bin/rpm --version
RPM version

[root@usch1ksv01 RPMS]# rpm --version
RPM version 4.8.0

[root@usch1ksv01 RPMS]# /usr/local/bin/rpm --checksig ypserv-2.19-10.el5_9.1.x86_64.rpm 
ypserv-2.19-10.el5_9.1.x86_64.rpm: RSA sha1 (MD5) (PGP) md5 NOT OK (MISSING KEYS: PGP#a8228ab5) 

[root@usch1ksv01 RPMS]# rpm --checksig ypserv-2.19-10.el5_9.1.x86_64.rpm 
ypserv-2.19-10.el5_9.1.x86_64.rpm: rsa sha1 (md5) pgp md5 OK

I don't understand why the signatures aren't working for the older version of RPM... I'm just doing an rpmsign --addsign , which clearly works for the new version but not the old. I've used both versions of RPM to try signing too.

I'm totally out of ideas, so any help would be greatly appreciated! Thanks!

share|improve this question
I storngly recommend creating a virtual machine for building the 5.x RPMs. – Michael Hampton Oct 2 '13 at 21:18
I'm not actually building any RPMs though, all I'm doing is signing them for a local repository. – user165222 Oct 3 '13 at 14:20
There's no real difference. – Michael Hampton Oct 3 '13 at 14:30

The "MISSING KEY" indicates that you have not done an rpm --import for the 0xa8228ab5 pubkey.

You can see the pub keys imported into an rpmdb rpm -q gpg-pubkey

After import (you may need to export an ascii armored pubkey using gnupg), you should see a gpg-pubkey with keyed in the version field.

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.