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I'm copying lots of files that have changed from one server to another using rsync. I know I can use the -n option to do a dry run, so I can see what files have been changed. However is it possible to get rsync to print a diff of the file contents that's changed? I'd like to see what's happening before doing a copy? Something I can save to a file and the apply with diff(1) later?

7 Answers 7

11

There might be a better way, but this might work, albeit not that efficiently:

 rsync -vrn / dest:/ > ~/file_list

Then edit test to remove the stats, then:

while read file; do
    diff $file <(ssh dest "cat $file")
done < ~/edited_file_list

Another Option:
You might also consider mounting the file system with something like sshfs/fuse, and then just using diff.

7
  • Note: I didn't test those commands ;-) Sep 4, 2009 at 11:31
  • Good start, but there's loads of extra output from rsync, such as the statistics, and "sending incremental file list", etc Sep 4, 2009 at 11:43
  • You could use --out-format="%f" Sep 4, 2009 at 11:49
  • If you use the out-format, drop the v, and grep -v 'skipping non-regular file' ... That should get it pretty clean Sep 4, 2009 at 11:51
  • Just checking if by chance there is a new / better method to rsync --diff two years later...
    – Déjà vu
    Jan 13, 2013 at 12:30
7

For create patch:

rsync -arv --only-write-batch=patch new/ old/

For apply it:

rsync -arv --read-batch=patch dir/

or use auto-generated script:

./patch.sh

Sources:

2

rsync can't do this natively, but if there's a possibility of using unison you can produce diff style format from that.

1

It's not possible natively because rsync only cares about binary differences between files.

You might be able to script it, using rsync's output. But it would be hackish.

I do believe it's natively possible with Unison though.

3
  • 1
    Is mine what you meant by hackish? :-) Sep 4, 2009 at 11:32
  • Absolutely, Kyle :D
    – Dan Carley
    Sep 4, 2009 at 11:35
  • That unison url does not work anymore.
    – Pedro Luz
    Jul 12, 2021 at 14:38
1

Why not just use something like diff (for text files) or xdelta (for binary files) to generate the diffs? Why do you need to specifically get something out of rsync?

2
  • I don't need rsync, but it need to be remote Sep 4, 2009 at 11:38
  • Oh noes, ssh!
    – womble
    Sep 4, 2009 at 12:58
1

To expand on Kyle's answer, this automates the process. Note that it is totally untested, probably pretty fragile, and may delete your computer and kill your dog.

#!/bin/bash

REMOTE=${1?Missing Remote Path}
LOCAL=${2?Missing Local Path}

# Trim trailing slash since we'll be adding it as a separator later
REMOTE=${REMOTE%/}
LOCAL=${LOCAL%/}

#Break it down
RHOST=${REMOTE%:*}
RPATH=${REMOTE#*:}

while read FILE; do
    diff -u ${LOCAL}/${FILE} <(ssh $RHOST "cat ${RPATH}/${FILE}")
done < <(rsync -vrn $REMOTE/ $LOCAL/ | sed '1d;/^$/q')
0

The rsync algorithm works by comparing binary chunks of the file. Such binary diff is not meant to be printable. There is a command called rdiff that uses the rsync algorithm to generate a binary diff, but I don't think it'd be useful for what you describe, it is commonly used to implement incremental backups.

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