Bash: Put a job in the background and then tail the log

Question

How do you make the escaping work so that the & is actually running the first command in the background?

# foo param1 param2 >> run.out &; tail -f run.out

Answer 1

Just drop the semicolon:

# foo param1 param2 >> run.out & tail -f run.out

Answer 2

You could use nohup:

nohup cmd & 

tail -f nohup.out

Answer 3

You need to put the backgrounded command in ()'s.

(ls -R / >>/tmp/list & ); tail -f /tmp/list

Sadly, this really backgrounds it. You won't be able to us %1 to get to its PID.

Answer 4

I just ran into this question as well, and solved it this way:

`foo param1 param2 >> run.out &` ; tail -f run.out

I don't know if the semantics are different.

For this specific case, the following is also useful:

foo param1 param2 | tee -a run.out