Extracting the last section of a log file

Question

How can I extract all the contents of a file which comes after a given line ? The line can be matched by exact contents or regular expression.

Answer 1

awk 'BEGIN { found=0; } /RE GOES HERE/ { found = 1; } found { print; }' $filename

Avoids multiple file traversals, so should (possibly) perform better for large files where the match is towards the end of the file.

Answer 2

tail -n +`egrep -n "pattern" "file_to_search.txt" | cut -d ":" -f 2 | tail -n 1` "file_to_tail.txt"

Answer 3

This simple awk program should do the job:

awk '/pattern/,""' filename

Answer 4

And also:

sed -n '/pattern/,$ p' filename