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I have files with lines in the following formats:

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12/16/09 17:56:30.211 rest of line...
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12/17/09 05:34:10.809 rest of line...
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How do I grep the lines out of this file that are between two dates, i.e. all the values for one day? I need to create a daily file with the contents from all the different server logs for that day.

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See also: serverfault.com/questions/40681/… –  MikeyB Dec 17 '09 at 21:36
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1 Answer

up vote 2 down vote accepted

Brackets can be used to give you a range of numbers. The carrot can match the start of a line. So..

grep "^12\/1[6-8]\/09" will give you everything that starts with 12/16/09, 12/17/09, and 12/18/09

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Thanks, I was so hung up on the timestamp that I didn't think of just using the day. –  Lance Roberts Dec 17 '09 at 19:52
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You could add a space after the year also, like grep "^12\/1[6-8]\/09 " to be sure. –  ℝaphink Dec 17 '09 at 19:55
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