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7

I still don't understand why /22 instead of /23 Because you have calculated your subnets wrong, and you are trying to use IPs from two different subnets. Or to put it a different way, if you use a /23 bit mask your starting address for the range, must be the first address for that range. 192.168.1.1 is not a starting address for any network described ...


2

It is unclear to me why you tried to setup a sub-interface. I suspect you just need to add this as just another secondary. interface FastEthernet0/1 ip address 192.x.x.x 255.255.255.128 secondary


2

On most of the networks I work with the router address is the first routable address (1, 129, and 193) in the subnet. This is by tradition, and not a requirement. Another option is to use the highest routeable address (126, 190, and 254) for the router. The lowest address in the each subnet (0, 128, and 192) is the network address and is not assigned. The ...


1

You haven't described the parameters of the exercise enough to make answering in a way that's acceptable to your instructor apparent. I'll take a stab for fun ('cuz, ya' know, I like answering questions for fun), though. Presumably, since you mentioned "domains", you have three DNS servers hosting Active Directory-integrated DNS zones. These three DNS ...


1

Those addresses are network addresses, which identify the specific network, and cannot be assigned to a host, which is what a router is. A router's interface must have a host address in order to identify that it is a member of that network and to know what interface to route traffic to.



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