Is it possible to find the command line of a running process with its pid
? the output of /proc/${PID}/cmdline
seems that it removes the space character to it is hard to read the output.
4 Answers
From: https://stackoverflow.com/questions/993452/splitting-proc-cmdline-arguments-with-spaces
cat /proc/${PID}/cmdline | tr '\000' ' '
cat /proc/${PID}/cmdline | xargs -0 echo
ps
can show this:
ps -o cmd fp <PID>
ps
can do a lot more. For infos, see man ps
-
3
For example 1
and 2
are PIDs.
Shortest way to show command:
ps 1
Explicit way:
ps --pid 1 2
Show only command field:
ps -o cmd 1
ps -o cmd --pid 1 2
Documentation: man ps
Put this script in your .bashrc file and source it
$ source ~/.bashrc
You can invoke it with command $pid which takes PIDs as command line argument and gives process name, user(process owner) as ouput eg:
$ pid 1 2 3 4 5 6 7 8 9 10
PID=1 Command=systemd User=root
PID=2 Command=kthreadd User=root
PID=3 Command=ksoftirqd/0 User=root
PID=5 Command=kworker/0:0H User=root
PID=7 Command=rcu_sched User=root
PID=8 Command=rcu_bh User=root
PID=9 Command=migration/0 User=root
PID=10 Command=watchdog/0 User=root
Script:
function pid(){
if [[ $# > 0 ]]
then
for i in $@
do
ps -e -o pid,comm,user | awk '{print "PID="$1, " Command="$2," User="$3}'| egrep --color "^PID=$i\W"
done
else
echo "Syntax: pid <pid number> [<pid number>]"
fi
}