How to specify GET path when sending web request to an IP with cURL?

Question

Using output from the command below,

% curl -v stackoverflow.com/questions       
* About to connect() to stackoverflow.com port 80 (#0)
*   Trying 198.252.206.16...
* Connected to stackoverflow.com (198.252.206.16) port 80 (#0)
> GET /questions HTTP/1.1
> User-Agent: curl/7.29.0
> Host: stackoverflow.com
> Accept: */*

I could do curl -X GET -H "User-Agent: curl/7.29.0" -H "Host: stackoverflow.com" -H "Accept: */*" 198.252.206.16 to replicate the request but how do I specify the GET /questions in my command?

Answer 1

stackoverflow.com/questions

= GET /questions

stackoverflow.com/87whjjgaas.asd

= GET /87whjjgaas.asd

23.123.123.123/questions

= GET /questions

for

curl -X GET -H "User-Agent: curl/7.29.0" -H "Host: stackoverflow.com" -H "Accept: /" 198.252.206.16

Answer is

curl -X GET -H "User-Agent: curl/7.29.0" -H "Host: stackoverflow.com" -H "Accept: /" 198.252.206.16/questions

:)

Answer 2

I needed to see how server behaved with certain "wrong" paths. To stop curl from normalizing a path, there is the --path-as-is option.

curl --path-as-is http://www.example.com/_cdn_assets_/./../font-awesome/4.3.0/css/font-awesome.css