reading stdin in shell

Question

#!/bin/sh
#myVar=`date`#case 1
#myVar=`cat /dev/stdin`#case 2
myVar=($(< /dev/stdin)) #case 3
echo $myVar
exit 2

case 1 works case 2 and 3 don't work. When I test with either 2 or 3; there is no output and the script never exits

What I eventually require is to read from the stdin written to by the postfix pipe

Calling a script with /bin/sh does not make it a bash script. — adaptr, Nov 2, 2012 at 12:55
Please fix your question to be more specific about what you are asking. — Ian D. Allen, Nov 6, 2021 at 15:00

MadHatter · Accepted Answer · 2012-11-01 20:41:56Z

1

#!/bin/bash
read fred
echo $fred

answered Nov 1, 2012 at 20:41

MadHatter

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I want to read multiple lines !
– Stewie
Nov 1, 2012 at 20:46
2

You should probably have said so, then. Do you want to read them to one variable, or many? More precision in the question will get you more functionality in the answers!
– MadHatter
Nov 1, 2012 at 21:11
2

@Stewie while read line ; do echo $line ; done
– ott--
Nov 2, 2012 at 13:10
@MadHatter I had written that "What I eventually require is to read from the stdin written to by the postfix pipe" which would explain that the data will span multiple lines, but I guess it wasn't enough and I'll take care next time :) Anyway initializing as bin/bash instead of bin/sh solved it thanks
– Stewie
Nov 2, 2012 at 13:40

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