I have a batch file which calls another batch file that exists in PATH directory (basically calling an executable with additional switches.)

: bar.bat:
foo.bat file1.txt
foo.bat file2.txt

In foo.bat:

foo.exe -t -s %1

bar.bat executes the first command but exits immidately (i.e. working on file1.txt only).

How can I make this batch file to invoke the other batch file more than once?

5 Answers 5


Use the CALL keyword:

call foo.bat file1.txt
call foo.bat file2.txt
  • 1
    <copied from Duncan Smart's answer, just to keep it together> In addition to @splattne's answer, use exit /b in the CALLed batch file if you need to return early.
    – Brad Bruce
    Commented May 26, 2009 at 11:33
  • 1
    You can also use goto :eof to return early. exit /b is usually only needed if you need the return code.
    – Joey
    Commented Jan 11, 2010 at 9:21
  • I don't why but I am struggling to get this to work, I have tried both exit /b and goto: eof. Is it ok to be appending the output of the CALLed bat? call foo.bat > myfile
    – SSH This
    Commented Oct 26, 2012 at 21:39

In addition to @splattne's answer, use exit /b in the CALLed batch file if you need to return early.


Another option (for compatibility with DOS prior to version 3.3 :-) ) is to call the command process with the child (/c) option and the name of the other batch file to process. That will also do a call instead of a chain, and will even work on truly ancient machines (just in case someone runs across this and cares). :-)


@echo off

echo WbLegalReport.cmd


cd I:\CFS\Batch\jarDir

echo %CD%


echo %CD%

echo WatchResrAddDeleted.cmd

echo %CD%


echo %CD%

What I am trying to do here is call these two batch files in a sequence.

Unable to do so.

help please.

Acutally it is failing at the child script, As the control does not return back to the main script


Sanket, don't call the batch file directly. Use the "CALL" command. See splattne's example.

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