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I want to implement the following command recursively

sed -i 's/href=\"1\//href=\"\/1\//g' ./*

so that it replaces all href="1 with href="/1 in all sub-directories. Is there a flag I can add to this command to achieve the results I want?

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find . -type f -print0 | xargs -0 sed -i 's/href=\"1\//href=\"\/1\//g'
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  • It should be -0 - it matches up with -print0 in the find - edited the post. – James Aug 20 '10 at 16:46
  • I find that find . -type f | xargs sed -i 's/href=\"1\//href=\"\/1\//g' can produce the same results. Will there be pitfalls to this approach? – John Dec 7 '19 at 16:54
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Per https://stackoverflow.com/a/5130044/833771, if the target directory is a Git or SVN root, you should use: find . -not \( -name .svn -prune -o -name .git -prune \) -type f -print0 | xargs -0 sed -i 's/href=\"1\//href=\"\/1\//g'

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