100

URLs always have this format:

<protocol>://<host>[:<port>]/[<path>][#<hash>]

The problem is that IPv6 uses colons, just like the separator of port and host, e.g:

2001:db8:1f70::999:de8:7648:6e8

But what if this is the host, and I want to connect to it with HTTP on port 100?

http://2001:db8:1f70::999:de8:7648:6e8:100/

The problem is the last colon. Since zero's are omitted with double colons (between 1f70 and 999), it's unknown if ':100' belongs to the IP or the port number. How can we know this?

1 Answer 1

137

The notation in that case is to encode the IPv6 IP number in square brackets:

http://[2001:db8:1f70::999:de8:7648:6e8]:100/

That's RFC 3986, section 3.2.2: Host

A host identified by an Internet Protocol literal address, version 6 [RFC3513] or later, is distinguished by enclosing the IP literal within square brackets ("[" and "]"). This is the only place where square bracket characters are allowed in the URI syntax. In anticipation of future, as-yet-undefined IP literal address formats, an implementation may use an optional version flag to indicate such a format explicitly rather than rely on heuristic determination.

3
  • 45
    It's worth pointing out that the brackets are not optional. It's the only unambiguous mechanism by which the browser can identify a numeric IPv6 address.
    – tylerl
    Nov 25, 2010 at 3:58
  • Shouldn't the port be inside the brackets?
    – jayarjo
    Dec 20, 2016 at 15:30
  • 3
    @jayarjo No, as the brackets are there to provide disambiguation between the IP address, which contains colons, and the port, which is separated from the IP address by a colon.
    – sysadmin1138
    Dec 22, 2016 at 13:26

You must log in to answer this question.