I want to get the size of all directories within a specific directory. I was thinking something like

find . -type d -exec du -sh {} \;

But that returns all directories recursively. How can I limit the depth?

6 Answers 6


Why use find at all and not simply glob for directories?

du -shc */
  • Well, the find option is more cross-platform, with the same command working on GNU/Linux and BSD/MacOSX systems (provided that -maxdepth 1 is specified before the -type d argument). The OSX version of du will give a syntax error with du -shc */.
    – platforms
    Commented Nov 29, 2012 at 7:49
  • 1
    Fair point, but do note that the poster used linux as a tag, so I was assuming linux in my answer. Commented Nov 29, 2012 at 7:51
  • This one is fine if you don't have hidden directories to include. Commented Nov 30, 2012 at 9:08
  • Easily adapted to hidden directories: du -shc */ .??*/ (The ?? is to exclude . and ..) Commented Nov 30, 2012 at 10:17
  • This actually IS best on Linux, because it allows you to ignore the current working directory, only listing the subdirectories (what the OP specified). Find includes the . directory. It also gives you the choice to see the sum total or not.
    – platforms
    Commented Dec 3, 2012 at 19:38

Add -maxdepth 1 to your find parameters.


This one should do the job efficiently :

du -hc --max-depth=1

One big difference I think of is that, when encountering hardlinked files, they will be counted only once. In a find loop, they will be counted once per base directory. [Is it correct english?]


You can use the -maxdepth option.


I'm using this one,

ls | xargs du -sh 

basically there are many ways to skin a cat :)


You can also do this:

du -ah .

What it does is to take the subdirectories of the current directory, find its individual's size and in the end, it prints the total size.

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