Bash - How to output two commands to file?

Question

I want to output two commands to a file. I want the exact time (date) AND temperature (sensors) to go to file every 5 minutes. I know how to output one command to a file, but two? How to write such script?

Answer 1

Something like this? (In a loop, cron, or whatever you're currently using.)

(date; my_sensor_command) >> log_file

Answer 2

Group all commands in parenthesis, because that will execute them in a sub-shell which you easily can redirect the output from:

 while sleep 5m
 do
         (date +%Y-%m-%d_%H:%M | tr -d '\012'; echo -n ' '; \
         /etc/rc.d/init.d/lm_sensors status | grep '^CPU Temp') >> /your/log/file

 done

Answer 3

If I understand your question right--you want to output two values to the same file--then this might be what you are looking for:

TIME="`date`"
SENSOR="56"

echo "$TIME $SENSOR" >> /path/to/a/file

Answer 4

Maybe I am misunderstanding the question, but it looks like all the answers are appending to one file. I read your question to be that you want the same output in 2 files. If that was what you are looking for, tee is a way to accomplish that:

echo "Stuff to output"|tee -a file1 file2

Answer 5

I know it's and old post but i needed to output the result of over 10 commands to a file, to work with this file and with @retracile answer i done this (simple & easy):

#!/bin/bash

(
command1
command2
command3
MORE COMMANDS
) > OUTPUT_FILE

cat OUTPUT_FILE

# WORK WITH OUTPUT_FILE
...

Answer 6

Refering to hlovdal post, you can set a cron like this:

$ crontab -e


*/5 * * * * (echo date +%Y%m%d%H%M%S | tr -d '\012'; echo -n ' ';  sensors | grep "CPU Temp:" | awk '{ print $3 }' )>> /var/log/sensors.log

Answer 7

Assuming you want the date and value on the same line:

sepChar='_'  #Separator character, for later processing
echo "$(date '+%Y%m%d %H%M%S')$sepChar$(mySensorCmd)" >> outputFile.log