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I've a very low priority level program who consume large of memory. I need to free RAM for other programs. My objective is to kill -STOP <pid> this process and ```kill -CONT when i need it. But RAM consumtion still problematic.

So:

Is it possible to run program only in swap ? If yes how ?

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  • Add more RAM to your server...?
    – Dan
    Nov 16, 2014 at 17:38
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    Effectively you are asking if you can make a low priority process consume all your I/O. Even if it was possible, it sounds like a silly thing to do.
    – kasperd
    Nov 17, 2014 at 0:56
  • My objective is to kill -STOP <pid> this process and kill -CONT <pid> when i need it. But RAM consumtion still problematic.
    – bux
    Nov 17, 2014 at 8:12

1 Answer 1

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No. Things that are swapped out are, by definition, not in memory and not eligible to be executed.

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  • I read of IBM system I/AS 400 allow to run swapped objects (I agree it isn't really swapped, since it doesn't make distinction between swap and RAM address space). Nov 16, 2014 at 20:57

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