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A company has been allocated all the IP addresses in the range 134.7.1.XXX, and needs to create three (3) subnets. The first subnet needs to be twice the size of the other 2

Is the answer simply:

Subnet 1: 134.7.1.000 - 134.7.1.499

Subnet 2: 134.7.1.500 - 134.7.1.749

Subnet 3: 134.7.1.750 - 134.7.1.999

closed as off-topic by joeqwerty, Andrew B, dmourati, EEAA, masegaloeh Jun 24 '15 at 4:03

This question appears to be off-topic. The users who voted to close gave this specific reason:

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You should go and re-read the wikipedia article for subnetting. A basic grasp of IPv4 addresses will help you more with your homework than just copying answers off here.

You didn't explicitly state it in the question, but I'll assume you have a /24 network and want to divide it into one 1x /25 and 2x /26 So you end up with 134.7.1.0/25, 134.7.1.128/26 and 134.7.1.192/26

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    Please do not help people who are spewing their homework questions here without any bit of research on their own. Doing so does nothing but enable the type of brain-dead behavior that is already all-too present at SF and in Sysadmin in general. – EEAA Jun 24 '15 at 2:18

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