A simple version of this question has been asked before (and links to VMware site for simple scenarios exist) - but this is a bit more complicated. I have 4 snapshot scenarios under VMware esxi 5.5:

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and I want to know what happens when I click "DELETE ALL" snapshots. Is this correct?

  • Scenario 1: A and B will be merged, and there will be NO more snapshots
  • Scenario 2: B will be thrown away, and there will be NO more snapshots
  • Scenario 3: A and B will be merged, C will be thrown away, and there will be no more snapshots
  • Scenario 4: A and B and C will be merged, D and E will be thrown away, and there will be no more snapshots.

According to VMware, deleting any snapshot merges it into the parent only if it is the current chain. But I think their article is poorly worded - and it conflicts with other VMware postings that suggest snapshots below the current (you are here) state in the current chain are simply discarded


When you choose "Delete all Snapshots", all of the snapshots go away and you end up with a single disk file.

  • 3
    Exactly what ewwhite says - you always end up at the 'You are here' stage and all snaps are deleted regardless of scenario. – Chopper3 Feb 14 '16 at 15:58
  • What does "GO AWAY" mean? Some posts say the are merged to the parent (if they are prior to the YOU ARE HERE), others say they are thrown away. Another posts says all are merged regardless of where YOU ARE HERE is. – TSG Feb 14 '16 at 16:08
  • Does it matter? It brings the VM into a consolidated state and removes the snapshots. – ewwhite Feb 14 '16 at 16:38
  • Yes - that's my whole question. In scenario 2: If changes are thrown away (ie: B is thrown away then I have reverted to state A. If changes are merged, then I have reverted to state B. Similarly, in scenario 4, are C and E merged into B, or are E and D thrown away and the disk reverts to state C – TSG Feb 14 '16 at 16:59
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    @Telium In the time you've taken to ask this question, you could have just tested each scenario and found out for yourself. – EEAA Feb 15 '16 at 16:00

1.First Scenario is last disk are ready in Write mode at B 2.You reverting from last disk and going to First disk data.... 3.same like 2 scenario but disk stage is different 4.scenario 4 is wrong because metedata will not create the new tree...called E ....

I hope you can understand my explanations

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