6

I have a DMARC report that includes:

<date_range>
  <begin>1500249600</begin>
  <end>1500335999</end>
</date_range>

How do I convert the dates to something human?

7 Answers 7

3

There was a converter from DMARC, here it is https://dmarcian.com/dmarc-xml/

And AFAIR there's also converted dates. Correct me if I'm wrong.

1
2

The date function in bash is quick and easy for casual conversion, such as when reading a DMARC report. On OSX:

$ date -jr 1606953599
Wed  2 Dec 2020 23:59:59 GMT

The -j flag prevents date from setting the date on your system. -r tells it there's a UNIX Time in seconds following, which is the DMARC report format for date_range fields.

2

I just got same question today and came to this post from Google search :)

However, it seems that site link, mentioned in previous answer, is no longer exist.

Here are working links to a few of such time converters:

https://timestamp.online

https://www.unixtimestamp.com

https://www.epochconverter.com

2

Links below are outdated, currently for similar purpose one can use https://www.unixtimestamp.com/

http://www.convert-unix-time.com/?t=1500249600 gives: timestamp 1500249600 means: In your local time zone: Monday 17th July 2017 10:00:00 AM UTC: Monday 17th July 2017 12:00:00 AM

http://www.convert-unix-time.com/?t=1500335999 gives: timestamp 1500335999 means: In your local time zone: Tuesday 18th July 2017 09:59:59 AM UTC: Monday 17th July 2017 11:59:59 PM

1
  • 2
    These links are obsolete. See @Zonder's response which has working links.
    – MSC
    Commented Oct 7, 2021 at 21:59
1

Try on Linux command line:

date --date='@1500249600'
Sun 16 Jul 2017 05:00:00 PM PDT
1

If you are on a system with MySQL such as MacOS, etc, open up a CLI and type

mysql> select from_unixtime(1500249600);

You'll get: +---------------------------+ | from_unixtime(1661212800) | +---------------------------+ | 2022-08-22 17:00:00 | +---------------------------+ 1 row in set (0.02 sec)

0

If you are on a system with MySQL such as MacOS, etc, open up a CLI and type

mysql> select from_unixtime(1500249600);

You'll get:

+---------------------------+
| from_unixtime(1500249600) |
+---------------------------+
| 2017-07-16 17:00:00       |
+---------------------------+
1 row in set (0.02 sec)

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