How to get a list of usernames assigned to a group in FreeBSD 11.1?

This Question asks for a list of users or a list of groups.

This Question asks for users who happen to be members of multiple specific groups.

➥ But how to ask simply for a list of users currently assigned to a single specific group, such wheel?

I prefer a solution in a single command if possible. But if not feasible, a script would be useful and educational.

  • Is a moderately complicated script parsing /etc/passwd and /etc/groups OK, or do you want a system command? – Law29 Dec 2 at 21:52
  • @Law29 Either, or both. I added note in Question. – Basil Bourque Dec 2 at 21:57
  • 2
    Why not just getent group groupname? – Nasir Riley Dec 2 at 22:02
  • @NasirRiley Can you show example? – Basil Bourque Dec 2 at 22:03
  • @BasilBourque It's just like I typed it. Replace groupname with the group that you want. – Nasir Riley Dec 2 at 22:12

https://www.cyberciti.biz/faq/linux-list-all-members-of-a-group/ thread show multiple ways of doing this. I personally prefer members method. but the method below is native and works well.

$ grep 'grpup-name-here' /etc/group
$ grep 'ftponly' /etc/group
$ grep -i --color 'ftponly' /etc/group

Disregarding system scripts like getent, users can be in a group in two ways: either it is their principal group, defined in /etc/passwd, or they have it as a secondary group in /etc/groups.

GROUPID=1000
sed -rn "s/^[^:]*:[^:]*:$GROUPID://p" < /etc/group | tr ',' '\n'
sed -rn "s/^([^:]*):[^:]*:[^:]*:$GROUPID:.*/\\1/p" < /etc/passwd

Should do it nicely. awk would probably look nicer...

GROUPID=1000
awk -F: -v "g=$GROUPID" '{if ($3==g) print $1;}' /etc/passwd
awk -F: -v "g=$GROUPID" '{if ($3==g) print $4;}' /etc/group | tr ',' '\n'

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